Finding a root of f(x) = cos(x):
eps_step = 1e-5;
eps_abs = 1e-5;
N = 100;
x = 0.2;
for i=1:N
xn = x - cos(x)/( -sin(x) );
if abs( x - xn ) < eps_step && abs( cos( xn ) ) < eps_abs
break;
elseif i == N
error( 'Newton\'s method did not converge' );
end
x = xn;
end
xn
What happens if you start with smaller values of x? Why?
Copyright ©2005 by Douglas Wilhelm Harder. All rights reserved.


